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Wavenumber

Compute the angular wavenumber k = 2π/λ (rad/m).

k (rad/m)

Wavenumber: k = 2π/λ

The wavenumber tells you how many oscillations fit into a unit of distance: k = 2π/λ, expressed in rad/m. Think of it as the spatial cousin of angular frequency ω = 2πf. Where ω counts cycles each second, k counts radians across each metre. Chemists working in spectroscopy lean toward the leaner form ν̃ = 1/λ (no 2π), reported in cm⁻¹. You'll see visible light around 12,500–25,000 cm⁻¹, mid-infrared from 400 to 4000 cm⁻¹, and microwaves below 33 cm⁻¹. Example: λ = 0.5 m gives k = 2π/0.5 ≈ 12.57 rad/m, and a green photon at λ = 500 nm comes out at k ≈ 1.26·10⁷ rad/m.

Applications: optics, IR spectroscopy, solid-state physics

Wavenumber is the everyday coordinate in IR and Raman spectroscopy, where bands at specific cm⁻¹ values flag functional groups (C=O near ~1700 cm⁻¹, O–H near ~3300 cm⁻¹). It also drives the Fourier transform that connects position-space and k-space in quantum field theory, indexes the Brillouin zone in crystal-lattice physics, and turns up in the dispersion relations ω(k) that tell you how each frequency moves through a medium such as optical fibres, plasmas, or phonons.

FAQ

Why two definitions (with and without 2π)? Physicists stick with k = 2π/λ (rad/m) because it pairs cleanly with ω in the phase kx − ωt. Spectroscopists reach for ν̃ = 1/λ (cm⁻¹) since it tracks directly with photon energy.

How does k relate to photon momentum? Through de Broglie, p = ℏk. A larger k means a shorter wavelength, which means more momentum and more energy.

What's k for visible light? Roughly 10⁷ rad/m, so well over a million radians per metre. That happens because λ is only hundreds of nanometres.

Can k be negative? Not as a magnitude. The wavevector k, though, can point any way it likes, and its sign marks which direction the wave travels (say +k to the right, −k to the left).

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