Reservoir Recovery Factor
Compute a reservoir's recovery factor, RF = (Np/N)·100%, the fraction of the original oil (N, or OOIP) that will actually be produced (Np). It is one of the most important — and uncertain — numbers in the industry: primary recovery (natural energy) is usually 5–15%; with secondary recovery (water/gas injection) it rises to 30–50%; and advanced methods (EOR) can go further. It defines the field's economic value. Enter the cumulative production and the original oil in place.
Resultado
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Fator de recuperação do reservatório
Aqui está a verdade incômoda do petróleo: a maior parte dele fica no subsolo. O fator de recuperação FR = (Np/N)·100% mede que fração do óleo original (N, o OOIP) será de fato extraída (Np). E os números são humildes: a recuperação primária, que usa apenas a energia natural do reservatório (gás dissolvido, capa de gás, influxo de água), tira tipicamente só 5 a 15%. A recuperação secundária — injetar água ou gás para varrer o óleo e manter a pressão — eleva para 30 a 50%. E os métodos avançados (EOR: injeção de vapor, polímeros, CO₂, surfactantes) podem espremer mais alguns pontos, a custo alto. Cada ponto percentual de recuperação, num campo gigante, vale bilhões — por isso a indústria investe tanto em entender e melhorar esse número. O FR é também o que separa o óleo presente (geológico) das reservas (economicamente produzíveis). Informe a produção acumulada e o óleo original in place.
Related Tools
Recoverable Oil Reserves
Compute the recoverable oil reserves by multiplying the original oil in place (OOIP) by the recovery factor (%). While the OOIP is the total volume present in the rock, only a fraction is technically and economically extractable — those are the reserves that actually have value and enter oil companies' books. It is the number behind asset valuations and investment decisions. Enter the OOIP and the recovery factor.
Oil in Place (OOIP)
Compute a reservoir's original oil in place (OOIP) by the volumetric method, OOIP = 7758·A·h·φ·(1−Sw)/Boi, in stock-tank barrels (STB). It combines the reservoir area (acres), the porous thickness (ft), the porosity (φ), the water saturation (Sw) and the oil formation volume factor (Boi). The constant 7758 converts acre-feet into barrels. It is the basis of any oil-field evaluation. Enter the area, thickness, porosity, water saturation and Boi.
Mining Recovery
Compute the mining recovery, R = (mined ore / in-situ ore)·100%, the fraction of the ore originally present in the deposit that is actually extracted. Not all ore is recoverable: support pillars, blasting losses and contacts leave part behind. Together with dilution, it defines the extraction efficiency and the mineable reserves. Enter the mined ore and the in-situ ore.
Oil Formation Volume Factor (Bo)
Compute the oil formation volume factor (Bo) by dividing the volume the oil occupies at reservoir conditions by the volume it occupies at the surface (stock-tank barrels). Bo is always greater than 1 because, in the reservoir, the oil is hot and has dissolved gas, occupying more space; as it rises and loses gas and heat, it shrinks. It is essential to convert reservoir volumes into surface production. Enter the volumes at reservoir and surface conditions.
Axle Load Equivalency Factor
Computes how many passes of the standard axle are equivalent to one pass of the real axle, using the power law of pavement design: factor = (axle load ÷ standard axle load) raised to the damage exponent. This factor is what converts a traffic count into the number N of standard axle repetitions, which in Brazil is the 8.2 tf, or 80 kN, single axle with dual wheels. The exponent amplifies overload brutally: an axle 20% heavier than the standard does not consume 20% more pavement but 2.07 times as much, which is why a single overloaded truck weighs more on the life of the road than thousands of cars, whose factor is practically zero. The exponent is an input rather than fixed at 4, the AASHTO value known as the fourth power law, because rigid pavement and fatigue cracking models work with exponents between 3 and 5 and the result shifts by a whole level depending on the choice. Enter the axle load, the standard axle load and the damage exponent.
Buller-Woodrow Loss Factor
Estimates the loss factor of a distribution feeder from its load factor using the empirical Buller-Woodrow relation: loss factor = k × load factor + (1 − k) × load factor squared. The loss factor is the ratio of average loss to peak loss over the period, and it is what turns the instantaneous loss measured at peak hour into energy lost over the month without needing a recorded load curve. Because Joule loss varies with the square of the current, the loss factor always sits below the load factor, and the lower the load factor the lower the ratio between them: at a load factor of 0.20 the loss factor is under half of it, while at 0.80 it sits around 86% of its value. The coefficient k is an input rather than fixed at 0.30, the classic Buller-Woodrow value for distribution networks, because utilities recalibrate k between 0.15 and 0.50 according to the feeder load profile. Enter the load factor for the period and the coefficient k.
The results provided by this tool are for general informational and educational purposes only and do not constitute professional, financial, medical, legal, tax or accounting advice. Always confirm important decisions with a qualified professional and official sources.