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Truncated Cone Volume Calculator

Compute volume and lateral area of a truncated cone: V = (π·h/3)·(R²+r²+R·r). For containers and construction.

Volume of a frustum of a cone

A frustum (truncated cone) is a cone with its top cut off by a plane parallel to the base. The volume is V = (πh/3)·(R² + r² + R·r), where R is the larger radius, r the smaller and h the height between the two circular faces. It generalises to any frustum as V = (h/3)·(A₁ + A₂ + √(A₁·A₂)). Example: R = 10 cm, r = 5 cm, h = 12 cm → V = (12π/3)·(100 + 25 + 50) = 700π ≈ 2,199 cm³. When r = 0 the formula collapses to the regular cone (πR²h/3).

Applications

Buckets, conical cups, lampshades, paint cans, margarine tubs and many supermarket packages have a frustum shape. Used in engineering for cooling towers of power plants, hoppers and silos, and in marketing for calculating product volume in non-cylindrical packaging.

FAQ

What if r = 0? It becomes a regular cone with volume V = πR²h/3.

And if R = r? The result is a cylinder, V = πR²h.

Does the formula work in litres? Yes — use cm for the dimensions and divide cm³ by 1,000 to get litres.

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The results provided by this tool are for general informational and educational purposes only and do not constitute professional, financial, medical, legal, tax or accounting advice. Always confirm important decisions with a qualified professional and official sources.