1001Ferramentas
📳 Calculators

Ball Pass Frequency, Outer Race (BPFO)

Computes the ball pass frequency of the outer race (BPFO), the signature a localized defect on a bearing outer ring leaves in the vibration spectrum: BPFO = (number of elements ÷ 2) × shaft rotation frequency × (1 − element diameter ÷ pitch diameter × cosine of the contact angle). The result, in hertz, is the frequency at which a peak appears every time a ball or roller rides over the flaw; because it is not an integer multiple of shaft speed, it is distinguishable from unbalance and misalignment, which show up at 1× and 2× rotation. Since the races slip slightly, the measured frequency usually falls 1% to 2% below the theoretical one, so look for the band rather than the exact line. A 6205 deep-groove ball bearing has a BPFO near 3.6 times shaft speed, and it is always worth checking that BPFO plus the inner race frequency equals exactly the number of elements times the rotation frequency. Enter the number of rolling elements, the shaft rotation frequency, the rolling element diameter, the pitch diameter and the contact angle.

Result

BPFO: pinning an outer race fault in the spectrum

A vibration analyst pulls a spectrum off a motor-pump, finds half a dozen peaks between 100 and 200 Hz, and has to decide whether the machine stops this weekend or waits for the next route. Without the theoretical BPFO worked out before the walk, that spectrum tells him nothing: every peak becomes a suspect and the call reverts to the mechanic's ear. Both mistakes bite — swapping a healthy bearing over a structural looseness peak, or missing an outer race spall while it still shows up only in the envelope band and the overall level has yet to move.

The math reads BPFO = (n ÷ 2) × fr × (1 − (d ÷ D) × cos α). Here n is the rolling element count, fr the shaft speed in hertz, d the ball or roller diameter, D the pitch diameter (the circle through the centres of the elements) and α the contact angle in degrees. Only the ratio d ÷ D enters, so millimetres or inches work equally well provided both fields share one unit. The answer usually lands near 0.4 × n times shaft speed; with the screen defaults, 4.93 times. The check that never fails: BPFO plus BPFI must equal n × fr exactly.

The formula assumes pure rolling with no slip, the outer race clamped in the housing and the inner race turning with the shaft. Flip that arrangement, with a rotating outer ring, and the two frequencies swap roles. Axial load and internal clearance shift the effective contact angle, which is why the measured line sits 1% to 2% under the computed one: the elements creep slightly on every revolution. The classic unit slip is typing shaft speed in rpm into a hertz field. 1500 rpm equals 25 Hz, and whoever forgets to divide by 60 goes hunting a peak at 7.4 kHz.

Frequently asked questions

How does the screen reach 123.251 Hz from the defaults?
The defaults describe a 12-element bearing on a shaft turning at 25 Hz, that is 1500 rpm, with 12 mm balls, a 65 mm pitch diameter and a 15 degree contact angle. The ratio 12 ÷ 65 works out to 0.1846; multiplied by the cosine of 15 degrees, 0.9659, it gives 0.1783; one minus that leaves 0.8217. Since 12 ÷ 2 × 25 = 150, the product closes at 123.251 Hz, printed with three decimals. That equals 4.93 times shaft speed, and on the route the real peak should land between 121 and 123 Hz, just under the theoretical line.
Mine is a deep-groove ball bearing. Which contact angle?
Zero. The field arrives preloaded with 15 degrees because the worked example is an angular contact bearing, but a deep-groove ball bearing under purely radial load has no contact angle, and neither does a cylindrical roller bearing. Switching 15 to 0 while keeping the other defaults lowers the answer from 123.251 to 122.308 Hz, under 1%, which is why many analysts skip the term altogether. On a 40 degree angular contact bearing the weight shows: the same set climbs to 128.786 Hz. The field accepts 0 up to but excluding 90 degrees.
Why did the message asking me to check the entries appear?
The page declines the calculation in four cases: element count, shaft speed, element diameter or pitch diameter at zero or below; element diameter greater than or equal to the pitch diameter; a negative angle; and an angle of 90 degrees or more. By far the most frequent cause is swapping the two diameters, typing 65 into the ball field and 12 into the pitch field. An empty field behaves differently: no warning shows, and the result simply falls back to a dash until every box holds a number again.

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The results provided by this tool are for general informational and educational purposes only and do not constitute professional, financial, medical, legal, tax or accounting advice. Always confirm important decisions with a qualified professional and official sources.