Rail Thermal Force (CWR)
Calculate the axial thermal force in a continuous welded rail (CWR), F = E·A·α·ΔT, from the steel elastic modulus E (Pa), the rail section area A (m²), the thermal expansion coefficient α (1/°C) and the temperature change ΔT from the neutral temperature (°C). In CWR — where rails are welded into hundreds-of-metre or kilometre strings, removing joints — thermal expansion is PREVENTED by track fastening, so a temperature change, instead of changing length, generates a huge internal axial force: compression in heat (risk of track buckling, which misaligns the rails) and tension in cold (risk of rail or weld fracture). Since the force does not depend on length (only section and ΔT), it can reach hundreds of kN. So CWR is installed at a neutral (stress-free) temperature chosen mid-range, minimizing compression and tension extremes. This is essential to modern track safety and to set the laying neutral temperature. Enter the elastic modulus, section area, expansion coefficient and temperature change.
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Rail thermal force (CWR)
The axial thermal force in continuous welded rail (CWR) is F = E·A·α·ΔT, computed from the elastic modulus of the steel E, the rail cross-sectional area A, the coefficient of thermal expansion α and the temperature change ΔT relative to the neutral temperature. Continuous welded rail — rails welded into strings hundreds of meters or kilometers long, doing away with the joints and with the classic 'clickety-clack' of older trains — gives a far smoother, quieter and longer-lasting track, but brings one critical problem with it: thermal expansion is restrained by the fastenings. Since the rail cannot change length, a temperature swing builds up a huge internal axial force: compression in hot weather (with the dreaded risk of buckling — lateral misalignment of the track into snaking curves that can derail trains) and tension in cold weather (risk of brittle fracture of the rail or of the welds). The unnerving detail is that the force does not depend on the length of the rail — only on the section and on ΔT — and can reach hundreds of kN even in a modest rail section. Track engineers handle this by installing CWR at a carefully chosen neutral temperature (stress-free or rail laying temperature) in the middle of the thermal range expected in the region, so the compressive extreme in summer and the tensile extreme in winter stay balanced and within safe limits. Computing this force is essential for the safety of modern permanent way, for setting the neutral temperature and for designing the expansion joints at the ends and at other critical points. Enter the elastic modulus, the section area, the expansion coefficient and the temperature change.
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Railway Cant (Superelevation)
Calculate the theoretical equilibrium cant (superelevation) of a railway curve, h = (B·V²) ÷ (127·R), from the dynamic gauge B (mm, distance between rail centers, ~1500 mm on standard gauge), the speed V (km/h) and the curve radius R (m). Cant is the raising of the outer rail above the inner one in curves, tilting the track inward — so the train's weight component helps provide centripetal force, balancing the centrifugal acceleration felt by passengers and reducing wheel-rail lateral wear. Equilibrium cant fully cancels the unbalanced lateral acceleration for a given speed; in practice a lower cant is adopted, since trains run at varied speeds on the same curve, and construction limits (~150-160 mm) apply for comfort and overturning safety of stopped trains. The difference between equilibrium and applied cant is the cant deficiency (or excess). Enter the gauge, speed and curve radius.
Track Sleeper Count
Calculate the number of sleepers needed in a track section, N = length ÷ spacing, from the section length (m) and the sleeper spacing (m, center to center). Sleepers (cross-ties) are the transverse track elements that carry the rails, hold the gauge (correct rail spacing), transmit rail loads to the ballast over a larger area, and anchor the track against longitudinal and lateral movement. Sleeper spacing (the 'sleeper density', typically 0.55-0.68 m, or about 1500-1900 sleepers per kilometre) is a design parameter depending on axle load, speed and sleeper type (wood, concrete, steel): heavy-haul lines use closer sleepers (more per km) to better spread high loads. This is essential for quantity take-off and budgeting of railway construction or renewal, since sleepers are a main track input, and for laying logistics planning. Enter the section length and the sleeper spacing.
Railcar Axle Load
Calculate a rail vehicle's axle load, P_axle = total weight ÷ number of axles, from the gross weight of the wagon or locomotive (N, tare plus load) and the number of axles. Axle load is the most important parameter for track design: it is the force each axle transmits to the track (and, per wheel, to each rail), governing stresses in the rail, sleepers, ballast and subgrade. Railways are classified by their axle-load capacity: heavy-haul railways (such as ore lines) run at 30-40 tonnes per axle and need heavy rail, concrete sleepers and reinforced ballast; passenger and light-freight lines run lower loads. Exceeding the allowable axle load causes accelerated fatigue, permanent deformation and failures — so rolling-stock and track-class compatibility is strictly controlled. Axle load also limits maximum train weight and thus transport productivity. Enter the total weight and the number of axles.
Railway Minimum Curve Radius
Calculate the minimum railway curve radius for a design speed, R = (B·V²) ÷ (127·(h_max + I_max)), from the gauge B (mm), speed V (km/h), maximum allowable cant h_max (mm) and maximum allowable cant deficiency I_max (mm). The minimum radius is set by combining the two comfort/safety limits available to 'absorb' lateral acceleration at the desired speed: the maximum buildable cant (limited by overturning risk of slow/stopped trains) and the maximum deficiency allowed to passengers. The larger these limits, the smaller the radius for a given speed — but both have normative caps. This is central to railway alignment: it defines how sharp a curve can be without speed reduction. Sharper curves require slowing down, penalizing travel time and line capacity — so high-speed railways need huge radii (kilometers). Enter the gauge, speed, maximum cant and maximum deficiency.
Drawbar Pull
Calculate the available drawbar pull of a tractor, F = W × μ, multiplying the weight on the driving wheels W (kN) by the traction coefficient μ of the tire-soil pair. The result, in kN, is the pulling effort the tractor can exert on implements (plow, harrow, planter) — limited by soil grip, not engine power. The traction coefficient depends on soil and tire type (0.5 to 0.7 on firm soil; much less on loose or wet soil). Increasing the adhesive weight (ballast) raises the available force. Enter the adhesive weight and the traction coefficient.
Lorentz Force
Compute the magnetic force F = q·v·B·sin(θ) on a moving charge.
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